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Similarly, (u_{infty}(x)) is a super-solution to (3.6).
So z is a super-solution of problem (4.1).
Therefore, u ¯ is a super-solution of problem (1.1).
Then, ((overline{u}(t),overline{v}(t))) is a super-solution of (1.6).
Then it can be verified that v ( x, t ) is a super-solution of (1.1).
Since u ̲ is a super-solution of (4.7), ϕ cannot exist globally.
The solution to problem (1.1) is a super-solution of (4.7).
Furthermore, 1 l ≤ u l ≤ u k for k < l, and a super-solution (sub-solution) comparison theory holds for (2.2) (see [19]).
The reason is that it is difficult for Problem 3 to find a super-solution initial point (x^{0}) and the algorithm may not converge.
As for TLASM, we need to find a super-solution initial of the problem, which may usually bring about some numerical difficulties.
It can be verified that, for the case m = q < r < 1, a sufficiently large constant L is a super-solution of (1.1).
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Justyna Jupowicz-Kozak
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