Exact(1)
The inversion operator (Gen and Cheng 1997), shown in Fig. 6, selects a substring from a parent and flips it to form an offspring.
Similar(59)
Step 1: Select a substring from the first parent randomly.
The procedure of the order crossover operation is: Step 1: Select a substring from the first parent randomly.
According to Equation (4), we get the following: s (S A [ 6 ] ) = max { min { 5, 3 }, min { 1, 0 } } = max { 3, 0 } = 3. Position 10 in S corresponds to position 3 in the original sequence S2, so, as a result, we obtain s 2 (3 ) = 3, i.e. the longest substring starting at position 3 in S2 matching a substring from S1 has length 3 (the substring itself is ' ana').
A sequence read is a short substring from a genome.
Thus, to encode a substring, only a single code number, corresponding to that substring's index in the dictionary, needs to be written to the output file.
An RNA sequence A is a string over the alphabet { A, C, G, U } with length | A |. We denote the base at the i-th position of A by A [ i ] ; the substring from position i to j, by A [ i j ] ; such substrings of RNA sequences are subsequently called subsequences.
Here a is a substring that starting from the leftmost base of P and S a is the so-called projected database that contains all sequences that contain the substring a, where the last element of each occurrence of a is marked (the so-called a-locations).
In a duplicate-invert operation a substring is copied from x and inverted before being inserted into the target string y.
A substring of s from position i to j is the sequence s [ i, j ] : = s i s i + 1 … s j. s R and s ¯ denote, respectively, the reverse and the reverse complement of a DNA string s.
The local closed subforest similarity considered in [ 52] restrict the aligned region to consist of a contiguous subsequence (substring) from each of the two input sequences.
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