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Hence, is a subsolution of problem (3.3).
then is called a subsolution of problem (2.8).
Under the assumption that and for any, is a subsolution of problem (1.1)–(1.1).
Under the assumption that for any, is a subsolution of problem (1.1)–(1.1).
Thus, is a subsolution of problem (3.3) as well, and we deduce.
The inequalities (3.10 - 3.13) show that v1 x, t) is a subsolution of problem (1.1).
Similar(47)
A nonnegative measurable function (uinmathbb{E}) is called a weak subsolution of problem (1.1) int_{0}^{t} int_{Omega}bigl{ u_{t}phi+|nabla u|^{p-2} nabla ucdot nablabigl u^{m}phibigr -gamma u^{r}|nablabigl u^{m}phibigr -gammaleqlambda int_{0}^{t} int_{Omega}u^{r}|nabla,dtau|^{p}phibigr}l bounded test functions (0leqphiin C_{0}^{1}(Omega_{T})).
If, then for sufficiently small and any the function is a positive subsolution of problem (1.1).
Assume that (u_{1}in C^{1} overline{D})) is a positive subsolution of problem (6) and that (h:overline{D}timesmathbb{R}times mathbb{R}^{N}rightarrowmathbb{R}) is continuous function such that (h x,t,xi ge g(t)) for all (xinmathbb{R}^{N}), (xiinmathbb{R}^{N}), and (tin 0,|u_{1}|_{L^{infty}(D)} ]).
Assume that (u_{1}in C_{0}^{1}(overline{D})) is a positive subsolution of problem (6) and that (h:overline{D}timesmathbb{R}times mathbb{R}^{N}rightarrowmathbb{R}) is continuous and such that (h x,t,xi ge g(t)) for all (xinmathbb{R}^{N}), (xiinmathbb{R}^{N}), and (tin 0, |u_{1}|_{L^{infty}(D)} ]).
In order to obtain an upper bound of (t^_{mathcal{N}}), we seek an unbounded subsolution of problem (3.1): textstylebegin{cases} underline{u}:= s(t)^{n} phi_{2}(x)^{2n}, underline{v}:=s(t)^{m} phi_{2}(x)^{2m}, end{cases} (3.2) with ({{n, m inmathbb{N}}} ) and (s(t)) satisfying Lemma 2.1.
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com