Sentence examples for a set of sum from inspiring English sources

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Accordingly, we derive a set of sum of squares feasibility tests leading to a stabilizing switching controller.

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The expression in (2) is the maximization of the minimum of a set of sums of concave functions of.

The classifier effectively learns a folding characteristic for each bit, which is realized as the weighted sum of a set of kernel functions.

Although each trial produces a set of IMFs, the sum of IMFs is not necessarily an IMF.

A special case of this problem is to find all possible partitions of a set of integers, which sum up to 0 (which, in turn, is a special case of the Knapsack problem, see (Horowitz and Sahni, 1974).

According to that concept, a state of affairs x is inefficient if there is some alternative state of affairs y such that, in y, there is a set of possible lump-sum transfers of wealth from those who are better off under y to those who are worse off, such that, with those transfers, everyone is at least as well-off under y as under x.

We build a set of the rank sums rS Cq where r s C q = r a n k (b r a w q x ) + r a n k (c o v q x ) + r a n k (i d e n t i t y q x ) x ∈ C q. Finally, the best mixed-ranking score (BMS) for the query q is defined as the largest rank sum r in rS Cq, B M S q = max (r r ∈ r s c q ).

A Multivariate ANOVA was also conducted on a set of all pollutants combined (Sum 36 PCBs, HCB, pp-DDE, pp-DDT, Sum 10 PBDEs, Sum 3 HBCDs and nine metals).

A Multivariate ANOVA (MANOVA) was conducted on a set of all pollutants combined (Sum 36 PCBs, HCB, pp-DDE, pp-DDT, Sum 10 PBDEs, Sum 3 HBCDs and nine metals).

However, a multivariate ANOVA conducted on a set of all pollutants combined (Sum 36 PCBs, HCB, pp-DDE, pp-DDT, Sum 10 PBDEs, Sum 3 HBCDs and nine metals) indicated statistically significant differences (F = 2.7; df = 20; p = 0.022).

As a result, we can achieve a set of rates such that (sum _{i=1}^{3}{R_{i}} geq frac {1}{2} C_{text {sum}}), and by the definition of normalized sum rate, we achieve (alpha = frac {1}{2}). 2 A cut Ω is a subset of (mathcal {V}) such that S∈Ω,D∉Ω, and (Omega ^{c} = mathcal {V} setminus Omega ). 3 The result for m=1 is trivial since we basically have an interference-free network.

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