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Then we have the following assertions: (1) (x_{0}) is a regular point of (3.1).
Then y ∈ W 0 1, p is a regular point of the Lagrangian (4.1) in the sense of Definition 4.1.
If, then is said to be a regular point (of ) and the map is called conformal at.
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Lemma 4.3 Let u ∈ A ad be a given element, and let y ∈ W 0 1, p be a regular point of the Lagrangian (4.1).
Proof It suffices to prove that if μ 2 is not an eigenvalue of ℜ, then μ 2 is a regular point of ℜ, i.e., μ 2 ∈ σ.
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As main result of the present paper we show that for a generic choice of their parameters the generalized polar varieties of V are empty or equidimensional and smooth in any regular point of V.
therefore z 0 is a regular point in view of Theorem 4.1.
Let the neighborhood (B subset widetilde{H}) of a regular point (x in T^+) be such that all points of the intersection (B cap T^+) are regular.
end{aligned} (38) From (38), it is clear that (r ( x,t ) ) is a regular surface, that is, every point of it is a regular point.
Let now B be a neighborhood (open in (widetilde{H})) of a regular point (x in T^+).
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