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Exact(39)
Y is a normal vector space.
(iii) Suppose that Y is a normal vector space.
Then the following statements are equivalent: (i) Y is a normal vector space.
The widget is represented by a plane with four corner vertices and a normal vector.
A normal vector is equivalent to the surface slope or derivative of the surface profile.
In the next theorem, we shall give a criterion for a normal vector space.
Similar(21)
(a) Normal vectors on a sphere; (b) normal vectors from a sphere translated into the origin of the coordinate system; (c) normal vectors from a sphere and their BFP N ; (d) normal vectors on a cylinder; (e) normal vectors from a cylinder translated into the origin of the coordinate system; (f) normal vectors from a cylinder and their BFP N [26].
The geometric interpretation shows that the shape operator of a plane which has a constant normal vector should be zero for both the discrete and the indiscrete cases.
Let be an arbitrary point where the boundary has a tangent hyperplane and let be a unit normal vector to.
where a and b are two constants and is a unit normal vector pointing outward of the boundary surface ∂V.
(5) Here, mathbf{P}(mathbf{u},p =2mumathbf{D}(mathbf{u} -p mathbf{u} -puad mathbf{D}(mathbf{u})=frac{1}{2} bI}l(nablamathbf{u}+ (nabla mathbf{u})^ bigr),qquad a unit tensor, (p^{0}(mathbf{x})) is a given function, anD}(mathbf{u}=frac{1}{s a unit normal vector to (S^{pm}).
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com