The phrase "a full component" is correct and usable in written English.
It can be used when referring to a complete part of a system or structure, often in technical or engineering contexts.
Example: "In order to ensure the device functions properly, we need to replace it with a full component."
Alternatives: "a complete part" or "an entire element".
CAPS offers a full component of skills, interests and personality assessment instruments that can help clarify academic and career direction.
Let C1 be a full component of G(M) − S and C2 be a full component of G(M) − S ′.
But then H2 does not contain a vertex adjacent to e, so H2 is not a full component, a contradiction.
Therefore if C is a full component of G M) − S we have N G (M ) (C ) = N G ′ (M ) (C ) = S, and it is also a full component of G ′ (M − S. By Lemma 2.5, S is a minimal separator of G ′ (M).
By Lemma 2.5, there exist two full components C, D of G - S, and by definition of a full component, there are paths connecting u and v in both C∪{ u, v} and D∪{ u, v}.
Since S is a minimal separator, there are at least two full components in G − S and because S ′ is parallel to S, there is a full component C1 of G − S that does not intersect S ′.
The set_source/set_model and set_bkg commands automatically convolve the ARF*RMF instrument response with the defined model expression before fitting, while set_full_model/set_bkg_full_model are available for manually applying (or not applying) the instrument response to individual components of a full, multi-component model expression.
Placement of the cleaning brush is also a key part of the design, since it allows for a full width component, where most robot vacuums use smaller brush bars that mean the bot needs to make more passes to finish the job.
The Pentagon has ordered a third carrier, the Kitty Hawk, to the region without its full component of fighter jets and other aircraft.
Then for each full component C of G − S ′, S has a vertex in C. (Lemma 3.10, [ 19]).
S ′ has at least two full components, and repeating this argument yields another full component C 2 ′ ≠ C 2 of G(M) − S ′ such that t (C 1 ) ∩ t (C 2 ′ ) ≠ ∅.
