Exact(29)
Then T and S have a common best proximity point.
Then f and g have a common best proximity point.
So, z is a common best proximity point of the mappings f and g.
Then z is a common best proximity point of the functions f and g.
Thus, we have ⋂ i = 1 ∞ F A ( T i ) ≠ ∅, i.e., Γ has a common best proximity point in A. □.
Then by the proof of the last theorem, z is a common best proximity of f and g. □.
Similar(31)
Allowing KMNADH and kcatNADH to vary did not provide a common best-fit value for KRedNADH.
Let A and B be closed ((A,Bneqphi)) be subsets of a complete metric space ((X,d)), and let (T Arightarrow B) be a continuous (mathcal{S} -contraction such that for any (x_{0} in A_{0}) such that (mathcal{S} -contractionute proximally, there exisucha unique common besthatoximity point in A such that d(x,Tx)=d(A,B) and d(x,mathcal{S}x)=d(A,B).
Then f, g, S, and T have a unique common best proximity point.
Then the functions f and g have a unique common best proximity point.
The following theorem is based on the existence of a unique common best proximity point for non-self-maps and also furnishes fixed point results in Cauchy metric spaces.
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