Sentence examples for Test changing from inspiring English sources

Test changing tables to see that they don't tip.

In sum, the survey data showed that test takers did change their preparation strategies for the second test, changing their focus from receptive to productive skills.

In a speech recognition score (SRS) test, changing the presentation level had the strongest effect on sentence recognition, followed by the presence of disyllabic words.

Assuming application of all the above independent changes that favour T: changing hospitalisation length and number of outpatient visits (related to management of adverse events), equalising the number of total cycles required for PLD and T and considering that the concomitant antiemetic drugs used with T have a zero cost (related to the cost of study drugs and their administration).

In our model, we consider the following events:  Sending a packet (Send, unconditional event)  Receiving a packet (Receive, conditional, e t = Receive | e t 0 = Send t 0 < t )  Dropping a packet (Drop, conditional, e t = Drop | e t 0 = Send t 0 < t )  Changing the channel of the radio interface (Channel Change, unconditional event).

dK1 class Focus S1 changing K2 S1 Propose T changing K1 S1 Affirm good T What's it changing?

Table 1 Time and distance between doctor's chest and seeds in the traditional treatment procedure: distance D mm), time t(s)   Applicators on tray Holding applicator Target tumor D t D t D t Changing 450 5 – – 900 5 Implanting 1000 15 300 15 350 15.

Furthermore, one can verify that π i + 1 ′ = π i ′ only when an adjacency of C is used by a DCJ in T changing π i to π i + 1 or when π i + 1 is produced from π i by a deletion of vertices that all belong to C. At least one such operation must always occur in T ; hence, d DCJ ind ≤ d DCJ ind - 1.

Since the sign of (1+2sin t) in (varphi(t)) is changing for (tin [0,T]), whether the balance condition in [17, 18] is satisfied remains unclear.

The change labeled 'Del TT' refers to the removal of two T residues, changing the normal seven consecutive T residues to five in the variant sequence.

Integrating (2.6) from 0 to t and changing the order of integration, we have u ( t ) = ∫ 0 t ( t − q s ) y ( s ) d q s + a 1 t + a 0, (2.7).