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If e i r < ε i, then from the complementary slackness condition ν e i 0 = ν e i 1 = 0. From the stationarity condition, we get ∇ e i r J = 0, but ∇ e i r J = 0 if and only if e i r = 0, a contradiction.

If the equality holds in (i), then from (25) and (26), we find begin{aligned} h(mathcal {D},mathcal {D})=0,~~~h(mathcal {D}^theta, mathcal {D}^theta )=0~~{text{ and }}~~h(mathcal {D}, mathcal {D} _theta )in Fmathcal {D}^theta.

(ii) If the function s ↦ Φ i (x, p, f s ) is continuous on I, then from (i) and Proposition 3.1 it follows that it is exponentially convex on I.   (iii) If the function s ↦ Φ i (x, p, f s ) is differentiable on I, then from (ii) it follows that it is exponentially convex on I.

(ii) If the function s ↦ Φ i ( x, y ; p, g, f s ) is continuous on I, then from (i) and by Definition 3, it follows that it is n-exponentially convex on I. □  .

If the function s ↦ Φ i ( x, y ; p, g, f s ) is continuous on I, then from (i) and by Definition 3, it follows that it is n-exponentially convex on I. □.

If f i (x, y) ≡ 0 for all (x, y) ∈ K × K in Theorem 2.1 and all i ∈ I, then, from the algorithm (D H ), we obtain, ∀ i ∈ I.

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Similar(51)

SWPs M i then result from the log mining process using clustering.

In Equation 14, if v = u i, then d k  = z i from Equation 8.

Moreover, z ∈ ⋂ i = 1 m A i. Then from Lemma 2 and Theorem 4 we immediately deduce the following theorem.

And I somehow separated who I was then from who I am now.

"I then heard from the local authority and a solictor that they were trying to sue us for negligence.

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