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Equation (8) can be transformed into ln left[ {ln frac{1}{1 - F x)}} right] = beta ln left( {x - gamma } right) - ln alpha, (9 by setting Y_{i} = ln left[ {ln frac{1}{{1 - F(x_{i} )}}} right],quad X_{i} = ln left( {x_{i} - gamma } right), (10 where x i is a random variable; the data satisfy the Weibull distribution when (X i, Y i ) complies with a linear distribution.
Similar(58)
I complied.
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Ought I comply with this request?
When officials give me an order, I comply.
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I complied but dreaded awakening this particular surgeon," he continued.
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I comply with their requests but for some reason, I become almost unable to speak.
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