He served 11 successive terms in the House and became chairman of its Education and Labor Committee in 1960.
China Business Council, as well as 4 successive terms on the board of the Governors of the American Chamber of Commerce – China (AmCham) and is Co-Chair of the Amcham Healthcare Forum.
Though Democrats outnumber Republicans in this district roughly three to one, they are of a very different stripe than the typical New York City version, having sent a Republican state senator, Serphin R. Maltese, to Albany for 10 successive terms until he was defeated by Mr. Addabbo in 2008.
In the classical Fibonacci sequence 1, 1, 2, 3, 5, 8, 13…each successive term, beginning with 2, is the sum of the two terms to its left; i.e., Fi = Fi − 1 + Fi − 2.
For example, the "sawtooth" function can be written as 2 sin x − sin 2x/2 + sin 3x/3 − ⋯); as successive terms in the series are added, an ever-better approximation to the sawtooth function results.
For example, the "sawtooth" function can be written as2 sin x − sin 2x/2 + sin 3x/3 − ⋯); as successive terms in the series are added, an ever-better approximation to the sawtooth function results.
It is also the ratio that is approached as successive terms of the Fibonacci sequence 1, 1, 2, 3, 5, 8... are divided by one another.
The LAR wedge developed due to 1) successive, short-term base-level falls during a relatively slow fall in long-term base-level followed by 2) superimposed, rapid falls in both long- and short-term base-level, and 3) multiple, short-term base-level falls during long-term base-level rise.
To be sure, able geonim such as Sherira and his son Hai (939 1038) exercised enormous influence over the Judeo-Arabic world through hundreds of legal responsa issued in the course of their successive terms (968 1038) at Pumbedita.
In 1912 Barkley was elected to the United States House of Representatives, where he served seven successive terms (1913 27) before his election to the Senate in 1926, where he served until 1949.
Consider two successive terms in (6) ( S [ n − j + 1 ] ) ∗ J S [ j − 1 ] + ( S [ n − j ] ) ∗ J S [ j ], and let us compute the block matrix in the left upper corner.
