Sentence examples for 1 sup from inspiring English sources

c 1 sup Q ?

1) Sup, Murkrow? 2) That's the new berry drawer, as teased in the trailer 3) Looks like berries can be purchased now, given the Shop icon in the upper right.

By the assumption, it is easy to see that lim n → ∞ ξ n = lim n → ∞ ( k n - 1 ) sup p ∈ F ϕ ( p, x n ) = 0. (3.5).

Proof of Theorem 3 Let g t, T ( x ) be the density of X t, T. Denote H 0 = sup t, T ≥ 1 sup x ∈ R g t, T ( x ), H Y, 1 = sup t, T ≥ 1 sup x ∈ R E [ Y t, T | X t, T = x ] g t, T ( x ), H Y, 2 = sup T ≥ 1 sup | t − j | ≥ M sup x ∈ R E [ Y t, T Y j, T | X t, T = x, X j, T = y ] g t, j, T ( x, y ), where M is some positive number.

where ξ n = ( k n − 1 ) sup p ∈ F ( T ) ϕ ( p, x n ), Π D n + 1 is the generalized projection of X onto D n + 1.

Proof It follows from 3.5 that there exists a finite constant M > 0 such that ∑ j = 1 m − 1 sup { a j ( x ) ; x ∈ C } ≤ M. (4.2).

Choose (R>max{R_{1}, sup W}), we have uneqmu Au,quad forall uinpartial B_{R}cap P_{c}, muin[0,1].

Our main idea, however, is to perform the same energy estimates based on the a priori assumption that N ( t ) : = ∑ i = 0 1 sup 0 ≤ τ ≤ t ∂ i ( u ( τ, x ) - w ( τ, x ) ) ∂ x i L ∞ ( R ) ≤ η (1.15).

In [9], the authors obtained the existence and multiplicity of positive solutions ( u ( t ) ≥ 0, v ( t ) ≥ 0 for all t ∈ [ 0, 1 ], sup t ∈ [ 0, 1 ] u ( t ) > 0, sup t ∈ [ 0, 1 ] v ( t ) > 0 ) by applying some theorems from the fixed point index theory.

In other words, if x01 and x02 are two values for which the graph crosses the vertical axis at point 0, two average-risk categories will be considered, as long as x 0 1 inf, x 0 1 sup and x 0 2 inf, x 0 2 sup do not overlap.

With f set to max (Fig. 6b) and (1-sup) as m, instead, as said above, it reaches the first quartiles of the results and is able to equal the AUROC of the alternatives at the lowest support.