Sentence examples for 1 intersects from inspiring English sources

The axis of rotation of joint 1 intersects with the center of the circular trajectory of joint 2. This intersection point gives the remote center of motion.

Then every solution of system (1) intersects the surface (Gamma_{i}) at most once.

Then every solution (x t):R_rightarrow G) of system (1) intersects each surface (Gamma_{i}), (iinunderline{Z^), exactly once.

In this section, we will seek the conditions which ensure that each solution of system (1) intersects each surface of discontinuity exactly once.

Red triangles represent a conversion to E F using V CNP  = −8 V so that the a linear fit of v sat vs. E F − 1 intersects the origin.

As shown in Figure 3, the x-isoline ({frac{dx}{dt}}=0) of system (1) intersects with x-axis at point (E^ K,0)), and the trajectory passing through point E intersects with impulse set (M_{I}) at point (E^{prime} tau,h)), and then (E^{prime} tau,h)) jumps to the phase set at point (E^((1-c)tau,h+ctau)). 1-c tau

In other words, the constant (varsigma_{1}) depends on the way (mathcal{T}_{mathcal{H},1}) intersects with (mathcal{T}_{mathcal{H},2}).

In this case, the line (U_{1}) intersects the boundary of the domain (varOmega_{text{d}}) at the points (O_{1}) and (O_{2}), and the line (U_{2}) at the points (O_{3}) and (O_{4}).

We know the periodic solution (widehat{SS^S}) is unique, where (Sinoverline{D_{0}D_{1}}). From Figure 6 we can see the orbit of system (2) starting from (D_{1}) intersects the line (x=h) at point (C_{1}), then jumps bake to the line (x= 1-p_{h})h+tau_{h} ) at point (D_{2}) due to impulsive effects.

For any point (S_{1}inoverline{DD'}), the orbit of system (2) starting from point (S_{1}) intersects a point in the line (x=h) which is denoted as (S_{1}^), then jumps to a point (S_{1}^in N) after impulsive effects.

Here, the line of quasi-static equilibrium in (48) intersects the line (v_{1}=V_{T}) before it intersects (v_{2}=V_{G}).