Sentence examples for 1 du from inspiring English sources

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Disgraceful... 9.15am GMT 9th over: South Africa 20-2 (Elgar 1, du Plessis 8) This is at least slightly interesting.

9.23am GMT 11th over: South Africa 20-2 (Elgar 1, du Plessis 8) The other things is, Chris, I kind of feel like the photos of food thing would be edging in on John Ashdown territory.

9.18am GMT 10th over: South Africa 20-2 (Elgar 1, du Plessis 8) As expected Johnson has a rest after his first 4-over burst and it's the spinner Nathan Lyon who is on to replace him in relatively foreign circumstances, from a scoreboard perspective.

Vaupel and Yashin point out an intrinsic defect of traditional survival analysis when they first explained the concept of population heterogeneity: i.e., so long as the time (t) of observation is long enough, the probability of any event will be close to 1 (Du 2008).

In this simulation, the probability of the tags randomly selecting the stationary probability p s in each frame is determined by the probability density function of the beta distribution [27] with parameters α and β: f x = x α − 1 1 − x β − 1 ∫ 0 1 u α − 1 1 − u β − 1 du, α, β > 0 ; 0 ≤ x ≤ 1.

Considering the following free boundary problem with logistic term in the same way as the problem (1), Du proved both spreading and vanishing can happen depending on the initial size: { u t − d Δ u = u ( α ( r ) − β ( r ) u ), t > 0, 0 < r < h ( t ), u r ( t, 0 ) = 0, u ( t, h ( t ) ) = 0, t > 0, h ′ ( t ) = − μ u r ( t, h ( t ) ), t > 0, h ( 0 ) = h 0, u ( 0, r ) = u 0 ( r ), 0 ⩽ r ⩽ h 0, (2).

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2.15pm BST 3rd over: South Africa 17-1 (Amla 1, Du Plessis 6) Kumar continues, and there's some sharp but still sensible running going on which keeps the score ticking over.

2.58pm BST 14th over: South Africa 116-3 (Duminy 22, De Villiers 1) Du Plessis fails to score from Ashwin's first delivery, the first dot ball since the middle of over 11.

Mohegan Sun, 1 Mohegan Sun Boulevard.

City 1, United 0?  .

This follows from begin{aligned} left| int _0^infty f u u^{s-1}du right|&le int _0^1 |f u u^{s-1}dua -1} du + int _1^infty |f(u)| u^{sigma -1} du &le A int _0^1 u^{-a+sigma -1} du + B int _1^infty u^{-b+sigma -1} du, end{aligned}since the firight|&leral exints if (sigma >a) and the second if (sigma

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